WebStep (1) : HCF of 625 and 3125 by using Uuclid's division algorithm is 3125=625×5+0⇒H CF of 625 and 3125 is 625. Step (2) : Now HCF of 625 and 15625 will 15625 =625×25+0 ⇒ HCF of 625 and 15625 is 625 . Hence HCF of 625, 3125 and 15625 is 625. nce required number is 625 . Topic: All topics View solution WebJan 25, 2024 · HCF of 625 and 3125 = 625 Now consider 625 and 15625 By applying Euclid’s division lemma 15625 = 625 × 25 + 0 ∴ HCF of 625, 3125 and 15625 = 625 Hence required number is 625 0 votes answered Jan 25, 2024 by Annu Priya (21.4k points) Subtract the given remainders from the numbers that are given :- 626 - 1 = 625 3127 - 2 …
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WebApr 22, 2024 · Therefore HCF of 625, 3125 and 15625 is: 5 × 5 × 5 × 5 = 625 Hence the largest number which divides 626, 3127 and 15628 and leaves remainders of 1, 2 and 3 respectively is 625 ← Prev Question Next Question → Find MCQs & Mock Test Free JEE Main Mock Test Free NEET Mock Test Class 12 Chapterwise MCQ Test Class 11 … Web626 – 1 = 625, 3127 – 2 = 3125 and 15628 – 3 = 15625 has to be exactly divisible by the number. Thus, the required number should be the HCF of 625, 3125 and 15625. First, consider 625 and 3125 and apply Euclid’s division lemma. 3125 = …
WebSep 26, 2024 · Now, we have to find the H.C.F. of 625, 3125 and 15625. First we find the HCF of 625 and 3125. By applying Euclid’s division lemma,a = bq+r Let a = 3125 and b = 625 3125 = 625 x 5 + 0. Here remainder is zero , and the last divisor is 625. So H.C.F. of 625 and 3125 is 625. Now,we find the HCF of 625 and 15625. WebOct 3, 2024 · To find HCF of 625, 3125 and 15625 first we will find HCF of 625 and 3125 and then we will find HCF of HCF of (625 & 3125) and 15625. Step (1): HCF of 625 and …
WebMar 12, 2024 · We can use this to figure out the HCF of 1250,9375,15625. This is how to do it. Step 1: The first step is to use the division lemma with 9375 and 1250 because 9375 is greater than 1250. 9375 = 1250 x 7 + 625. Step 2: Here, the reminder 1250 is not 0, we must use division lemma to 625 and 1250, to get. 1250 = 625 x 2 + 0. WebTherefore HCF of 625, 3125 and 15625 is: 5 × 5 × 5 × 5= 625. Hence the largest number which divides 626, 3127 and 15628 and leaves remainders of 1, 2 and 3 respectively is 625. Question 11. Find the greatest number that will divide 445, 572 and 699 leaving remainder 4, 5 and 6 respectively.
WebNotice that 625 = HCF (1250,625) = HCF (9375,1250) . We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma Step 1: Since 15625 > 625, we apply the division lemma to 15625 and 625, to get 15625 = 625 x 25 + 0 The remainder has now become zero, so our procedure stops.
WebFeb 28, 2024 · So, the HCF of 15625 and 625 is 625. Hence HCF of 625, 3125 and 15625 is 625. Note: During solving this question you can use any one of the methods, but the first … cypecad 2021 crackeado torrentWebJan 20, 2024 · Solution. Required number = HCF of (628 - 3), (3129 - 4) and (15630 - 5) i.e., required number = HCF of 625, 3125, 15625 To find HCF of 625,3125 and 15625 first we will find HCF of 625 and 3125 and then we will find HCF of (625 \& 3125) and 15625 . Step (1) : HCF of 625 and 3125 by using Uuclid's division algorithm is 3125 = 625 × 5 + 0 ⇒ H ... cyp eating disorder nhsWebThe simplest form of 15625 / 1000 is 125 / 8.. Steps to simplifying fractions. Find the GCD (or HCF) of numerator and denominator GCD of 15625 and 1000 is 125; Divide both the numerator and denominator by the GCD 15625 ÷ 125 / 1000 ÷ 125; Reduced fraction: 125 / 8 Therefore, 15625/1000 simplified to lowest terms is 125/8. MathStep (Works offline) bimpli facebookWebFind the prime factorization of 625. 625 = 5 × 5 × 5 × 5. To find the GCF, multiply all the prime factors common to both numbers: Therefore, GCF = 5 × 5. GCF = 25. MathStep … cypecad 2022 fullWebSince remainder is zero, therefore, HCF (1250, 9375 and 15625) = 625 Hence, 625 is the largest number which divides 1251, 9377 and 15628 leaving remainder 1, 2 and 3, respectively. Concept: Euclid’s Division Lemma Is there an error in this question or solution? 2024-2024 (March) All India (Set 2) Q 19.2 Q 19.1 Q 20 APPEARS IN cypecad 2023 + crackWeb30+125+625+3125+15625 . Add 5 and 25 to get 30. 155+625+3125+15625 . Add 30 and 125 to get 155. 780+3125+15625 . Add 155 and 625 to get 780. 3905+15625 . Add 780 and 3125 to get 3905. 19530 . Add 3905 and 15625 to get 19530. Examples. Quadratic equation { x } ^ { 2 } - 4 x - 5 = 0. Trigonometry. cypecad 2023 crackeadoWeb375 = 3 × 5 × 5 × 5. Find the prime factorization of 625. 625 = 5 × 5 × 5 × 5. To find the GCF, multiply all the prime factors common to both numbers: Therefore, GCF = 5 × 5 × … bimp hotline