WebZ 3 x2 dx = Z 3x 2=;dx (2) = 3x 1 + C Z 5 + cos d = 5 + sin + C (3) Question 4. You may use a calculator on both parts of this question. Part A. Imagine an elliptical oil slick that at … WebMay 15, 2009 · 由正弦定理可得: a/sinA=b/sinB=c/sinC=2R 又:bsinB-asinA= (b-c)sinC 则:b* (b/2R)-a* (a/2R)= (b-c)* (c/2R) b^2-a^2= (b-c)c b^2-a^2=bc-c^2 c^2+b^2-a^2=bc 则:由余 …
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已知 ABC的内角A,B,C的对边分别为a,b,c,若2csinC…
WebSep 15, 2024 · `sin5A=5cos^4AsinA-10cos^2Asin^3A+sin^5A` asked Dec 21, 2024 in Trigonometry by TanujKumar (70.8k points) class-11; trigonometric-ratios-of-multiple-and-submultiple-angles; 0 votes. 1 answer `sin5theta =` asked May 26, 2024 in Trigonometry by TanujKumar (70.8k points) class-11; Web30°在三角形ABC中,a/sinA=b/sinB=c/sinC,则csinB=bsinC 因为b=2csinB,所以csinB=b/2 b/2=bsinC,所以sinC=1/2,角C=30° 由正弦定理 1年前 追问 5 Kwanl 举报 第二问呢 回答问题 可能相似的问题 已知三角形ABC中角A,B,C的对边分别为a,b,c,且cos²(π/2+A)+cosA=5/4,b+c=√3 1年前 1个回答 已知三角形ABC中,角A,B,C的对边分 … Web三角形ABC中,根据正弦定理,a/sinA=b/sinB=c/sinC=2r,r为外接圆半径。 asinA+bsinB+√2bsinA=csinC,a2+b2+√2ab=c2,cosC= (a2+b2-c2)/。 2ab。 √2ab。 / … kirt tally repents